Subnetting Que

Ok, i consider myself to be average at subnetting, but I am lost doing this question

Which of the following IP addresses are broadcast addresses if the subnet mask is 255.255.255.240? (Choose three.)
75.32.75.15
205.16.35.11
199.254.129.111
129.130.17.143
135.22.55.93
105.33.62.213

Can anyone tell me how i can solve this specific question and others like these

Thanks

There are 4 remaining bits, so there are 16 (14 usable) hosts per subnet. The increment of the subnet addresses is 16 (x.y.z.0/28, x.y.z.16/28, x.y.z.32/28, x.y.z.48/28 etc.) so 75.32.75.15, 199.254.129.111 and 129.130.17.143 are broadcast addresses. If you add 1 to the final octet of each, 16 is a divisor.

HTH

Hey thanks for all the help, i was trying to do it myself yesterday and got it, it is pretty easy thanks for your comment still.