Some Cisco questions

Hi all,

I have posted some Cisco question weeks ago no one answered, anyway that's fine.

But I do have some questions which I am confused or can't figure it out.

1. How will the MAIN router dynamically learn a route to the 10.16.10.48/28 subnetwork ?

My though is with a static route. Can anyone tell me is it right ?

2. Which type of address is 192.168.17.111/28 ?

3. Which type of address is 192.168.17.134/29 ?

Please help me....

Hi all,

I have posted some Cisco question weeks ago no one answered, anyway that's fine.

But I do have some questions which I am confused or can't figure it out.

1. How will the MAIN router dynamically learn a route to the 10.16.10.48/28 subnetwork ?

My though is with a static route. Can anyone tell me is it right ?

2. Which type of address is 192.168.17.111/28 ?

3. Which type of address is 192.168.17.134/29 ?

Please help me....

--I'm just using my common sense here for your first question.
There are dynamic routing protocols like RIP, IGRP, EIGRP etc, which exchange Routing Tables periodically and learn about all the subnetworks so routers can route packets to remote networks.

--For 2 & 3 I don't understand what you mean, which type of address?. That said, /28 represents your SubNet Mask, which here it is 255.255.255.240 and /29, 255.255.255.248, which means you are borrowing 4 bits from the last octet to create extra subnetworks for the first one and 5 bits from the last octet in the second one.

Hope it helps.

Thanks for your reply.

For the question 1, the answer can be:

- with a Routing protocol
- with a Routed protocol
- with a static route
- with a directly connected eoute

For question 2 and 3 The answer can be:

Host address
Network address
Broadcast address
Multicast address

Thanks for your reply.

For the question 1, the answer can be:

- with a Routing protocol
- with a Routed protocol
- with a static route
- with a directly connected eoute

For question 2 and 3 The answer can be:

Host address
Network address
Broadcast address
Multicast address

--Now, is this some kind of CCNA exam for FallenZer0. I will FAIL.
1]. Routing Protocol.

2]If it is NOT Network Address, NOT Broadcast Address, NOT Multicast Address, then what is it?

Which type of address is 192.168.17.111/28 ?

In short, it's a 'broadcast' address.

The above address translates to:

Network (subnet): 192.168.17.96
Subnet mask: 255.255.255.240

Host Range: 192.168.17.97 to 192.168.17.110 (14 hosts)

Broadcast for this subnet is 192.168.17.111

Which type of address is 192.168.17.134/29 ?

In this question, the address is a 'Host' address.

The above address translates to:

Network (subnet): 192.168.17.128
Subnet mask: 255.255.255.248

Host Range: 192.168.17.129 to 192.168.17.134 (6 hosts)

Broadcast for this subnet is 192.168.17.135

If you have any more questions, let us know!

Cheers,

Chris and FallenZer0,

I would like to express many thanks for answering my question. I have found out the answer for Question 1 from here:

defoenet.com/ccna/r-v-r.htm

So it's with a Routing Protocol

I just want to be sure with my subnetting here:

Determine the number of useable networks and hosts for the IP address of 192.168.50.0/27

Based on the subnetting rules

I came up with 6 useable networks (2 to the power of 3, 3 which is the number of bits borrowed, which is 8 minus 2 which becomes 6, this is according to the 2nd rule of subnetting)

I came up with 30 useable hosts (2 to the power of number of bits remaining which is 5 so it's 32-2 which is 30)

In order for Host A to communicate with email server which are to be configured ?

My answer: IP Address, Subnet mask and Default gateway.

Other choice: Router name, switch name and NetBios name address.

Many2 thanks guys