subnet /23

A host on the network has been configured with the ip address
10.6.3.66/23 which two statements describe this ip address?
A. The broadcast address of the subnet is 10.16.3.255 255.255.254.0
B. This network is not subnetted
C. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
D. The subnet address is 10.16.3.0 255.255.254.0
E. The lowest host address in the subnet is 10.16.2.1 255.255.254.0

available host bits 9 bits, will provide upto 512 ip address
i am sure B and c is not the valid statement.A is the valid statement.
but i am confused whether to select D or E. please explain..

A host on the network has been configured with the ip address
10.6.3.66/23 which two statements describe this ip address?
A. The broadcast address of the subnet is 10.16.3.255 255.255.254.0
B. This network is not subnetted
C. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
D. The subnet address is 10.16.3.0 255.255.254.0
E. The lowest host address in the subnet is 10.16.2.1 255.255.254.0

available host bits 9 bits, will provide upto 512 ip address
i am sure B and c is not the valid statement.A is the valid statement.
but i am confused whether to select D or E. please explain..

First things first, break down the IP addressing scope...
10.6.3.66 / 23

---

10.6.0.0 / 23
***
10.6.1.255 / 23

---

10.6.2.0 / 23
***
10.6.3.66 / 23 <--- Your IP
***
10.6.3.255 / 23

---

Answers A and E work for me and here's why...

A is correct because the broadcast address is 10.6.3.255 / 23 (straight from the IP breakdown).

B cannot be right because the network is most certainly subnetted.

C makes me sad because the last valid host in the subnet is actually 10.6.3.254 / 23, not 10.6.2.254 / 23 (straight from the IP breakdown).

D doesn't work because the subnet address (I hate it when they call it that, I call it the Network ID) is really 10.6.2.0 / 23. Again they just changed up the third octet's number on you. Sneaky sneaky.

E makes me happy because the lowest usable IP address is indeed 10.6.2.1 / 23.

It really helps to draw out a breakdown of the IP scheme, or just do it in your head. You don't even need to fill in all the numbers. Most of your subnetting answers will be found in the breakdown, which is especially helpful on a test if you wanna just list the network IDs really quick in a long format and fill in any numbers you need for the subnet in question. Happy subnetting!!

Hi,

First things first, break down the IP addressing scope...
10.6.3.66 / 23

---

10.6.0.0 / 23
***
10.6.1.255 / 23

---

10.6.2.0 / 23
***
10.6.3.66 / 23 <--- Your IP
***
10.6.3.255 / 23

---

according to the above mentioned ip addressing, we can break up
10.6.0.0/23
10.6.1.0/23
10.6.2.0/23
10.6.3.0/23
***
10.6.3.66/23
***
10.6.3.255/23
why we are taking 10.6.2.0 as the network ID for the given address. please explain the breakup...

thnks.

The /23 subnet mask is 255.255.254.0. The "block size" is 256 - 254 (the non-255 octet, as I've mentioned before) and this is the third octet.

The network addresses are:

10.6.0.0
10.6.2.0
10.6.4.0
10.6.6.0

...
etc.
...

Each network has 512 addresses of which 510 are valid host addresses. This can be also be calculated from first principles by converting everything to binary.

Hi,

thanks for your clarification.