An admin wants to create 32 subnets on a block

An organization is granted the block 211.17.180.0/24. The administrator wants to create 32 subnets ??

a. Find the subnet mask.
b. Find the number of addresses in each subnet ??
c. Find the first and last addresses in subnet 1 ??
d. Find the first and last addresses in subnet 32 ??

check how many bits you need for the subnet.

Subnet your subnet with these extra bits to chop your big subnet in smaller subnets.

Then the rest is easy.

If you don't understand subnetting check the subnetting on this site.

(seems like you don't feel doing your homework?)

a. Assuming here that subnet zero is allowed. 32 subnets needs 5 bits as 2^5 = 32. So you need to borrow 5 bits from the fourth octet. So the subnet mask will be /24+5 = /29.

b. There are 3 bits remaining from the 8 bits of the fourth octet. 3 bits gives you 2^3-2=6 hosts in each subnet.

c. If subnet zero is counted in this question. Then network address of subnet 1 will be 211.17.180.8. So The first address is 211.17.180.8+1 = 211.17.180.9 and the last address is 211.17.180.8+7-1 = 211.17.180.14

d. I'll leave this for you to figure out