Regarding Supernetting/CIDR Analysis

Hi,
I feel the topic which you guys explained about is not entirely adequate ,Since therein you have supernetted the IP address
203.31.218.0 to 255.255.254.0 ie /23 which is easy to understand
Though you should have also explained as to how you got to the values mentioned in the Supernetting/CIDR chart

Say begining with

/14 yields 1024 Class C networks
/15 512
/16 256
/17 128

Now how do you get to the above values is it using the class A ,B or C network's
Actually I still feel there is a gap in the Explaination could Precise examples be given to figure out what you have put in the chart its all very confusing????

Rgds

Hi,

Sorry, I took this posting away, because it was on wrong place.

@Bruce18:

if you use the mask 252 in the 2nd octet of an ip address you have 2 bits left in that octet, plus 8 bits of the 3rd octet you have totally 10 bits free in order to build C-Class Subnets. That means 2^10 = 1024 C-Class Subnets.
If you continue like this, with the mask 254 you have 1 bit free in the 2nd octet and 8 bits in the 3rd octet, means 9 bits totally, means 2^9 = 512 C-Class networks and so on...

Rgds

... but as I just realized, the total number of hosts is wrong.
In my opinion the number of hosts is 1024 x 256 -2 (=262142).

rgds