- Posts: 251
- Thank you received: 0
Subnetting question [2048 or 8]???
16 years 5 months ago #26230
by Chojin
172.16.0.0/23 Would be your 1st Subnet (for 512 -2 users)
This would include 172.16.0.0 - 172.16.1.255
Your next subnet will start at 172.16.2.0.
From this point you See you need 200 hosts, and continue your count.
/24 would be sufficient.
so 172.16.2.0/24 is enough for your 2nd subnet
This is 172.16.2.0 - 172.16.2.255
Now for the 3rd you need 100 hosts.
Your next subnet starts at 172.16.3.0
So that would be 172.16.3/25 (128-2hosts)
Hope this helps m8.
CCNA / CCNP / CCNA - Security / CCIP / Prince2 / Checkpoint CCSA
Replied by Chojin on topic Re: Subnetting question [2048 or 8]???
i know that the first network would be 172.16.0.0/23 convert to binary and that would be x.x.00000001.11111111. how do i subnet /23 to the 2nd network (/24). hope you can show the binary form.
3 networks
500 host - 1st network
200 host - 2nd network
100 host - 3rd network
172.16.0.0/23 Would be your 1st Subnet (for 512 -2 users)
This would include 172.16.0.0 - 172.16.1.255
Your next subnet will start at 172.16.2.0.
From this point you See you need 200 hosts, and continue your count.
/24 would be sufficient.
so 172.16.2.0/24 is enough for your 2nd subnet
This is 172.16.2.0 - 172.16.2.255
Now for the 3rd you need 100 hosts.
Your next subnet starts at 172.16.3.0
So that would be 172.16.3/25 (128-2hosts)
Hope this helps m8.
CCNA / CCNP / CCNA - Security / CCIP / Prince2 / Checkpoint CCSA
Time to create page: 0.110 seconds