Subnetting Question..

Hello, I'm still learning the concept subnetting right now. I just got an subnetting assignment from my course and wondering if I done it correctly? One thing I'm really not sure how to do is the last part, the question ask about to assignment host on 3 PCs and find their range? I'm not sure how can I find that?

*There should be a diagram indicate 3 PCs. Each PC connecting to a Ethernet switch and each ethernet switch connecting to each other with a Serial Port (S0, S1..)*


Please help




IP assigned 142.204.0.0


Using the assigned IP address and the diagram above, answer the following questions:

Create a network addressing scheme that allows for 64 subnets

What is the Subnet mask?
A: 255.255.252.0


Write the correct IP addresses in the spaces below for each administrative task:

Assign SO R1 and S0 R2 to the 24th subnet:
A: 142.204.96.0


Assign the first 2 host addresses to S0 R1 and S0 R2 respectively

S0 R1: 142.204.96.1

S0 R2: 142.204.96.2


Assign S1 R2 and S0 R3 to the 25th subnet: 142.204.100.0

Assign the first 2 host addresses from this subnet to S1 R2 and S0 R3 respectively

S1 R2: 142.204.100.1

S0 R3: 142.204.100.2


Assign E0 R1, E0 R2 and E0 R3 to the 26th, 27th and 28th subnets respectively and assign the first host address in each subnet to the Ethernet port.

E0 R1 Subnet IP: 142.204.104.0 Host IP: 142.204.104.1

E0 R2 Subnet IP: 142.204.108.0 Host IP: 142.204.108.1

E0 R3 Subnet IP: 142.204.112.0 Host IP: 142.204.112.1


*Below is the part which I'm not sure about*
Assuming that each PC connected to R1, R2 and R3 is a DHCP server, assign the next host address in each subnet to each PC and then show a range of IP address that would be required to issue 500 addresses to connected workstations

PC1 R1: 142.204.4.1??? Range: __________

PC1 R2: 142.204.4.2??? Range: __________

PC1 R2: 142.204.4.3??? Range: __________


Thank You!

Anyone?

This is what dosn't make any sence to me...

PC1 R1: 142.204.4.1??? Range: __________

PC1 R2: 142.204.4.2??? Range: __________

PC1 R2: 142.204.4.3??? Range: __________

I have no idea where this is coming from.

It "SEEMS" they want you to show (learn) how to get a large number of ip addresses you need to increment the 3rd octet....

Not everyone knows that you can't just assign ip addresses 140.204.96.500

To get over 255 addresses you need to go from...
140.204.96.1 to 140.204.97.xxx /16

I'll look at it again if work calms down. Doing it all in my head i'm not "seeing the big picture"

Range

142.204.4.1
142.204.4.2
.
.
.
.
142.204.7.254

for the 1st subnet

here subnet mask is 255.255.252.0
the ip address which comes in between this range is valid if you want you can check by assigning any ip address for the machine you are working with the subnetmask of 255.255.252.0

let us work it out

consider the number of bits used in the host portion

that is
142.204.000001 00.00000001 = 142.204.4.1
142.204.000001 00.00000010 = 142.204.4.2
142.204.000001 00.00000011 = 142.204.4.3
.
.
.
.
.
.proceeds

.
.
.
142.204.000001 11.11111111 = 142.204.7.255

1st subnet ends here

now second subnet starts from

142.204.000010 00.00000001 = 142.204.8.1
.
.
.
:
.
142.204.000010 11.11111111 = 142.204.11.255

second subnet ends here

this is how it is proceeding