GM,
If I have understood your question correctly,
you would like to subnet a Class C network of 192.168.5.0 to 14 subnets, which will contain a max of 5 hosts per subnet;
The way to do this would be as follows:
We need to first calculate the amount of subnet bits we require to get 14 subnets...
2^3=8, no good.
2^4=16 ! This is what we want as its the closest to 14.
So we need 4 subnet bits reserved.
Analysis of last two octects of network/subnetmask in binary:
192.168.00000101.00000000
255.255.11111111.11110000
As you can see, the last octect contains 4 subnet bits (1111).
Here are the first few networks and ranges:
Network 1: 192.168.5.0
Range: 192.168.5.1 - 192.168.5.14
Broadcast: 192.168.5.15
Network 2: 192.168.5.16
Range: 192.168.5.17 - 192.168.5.30
Broadcast: 192.168.5.31
Network 3: 192.168.5.32
Range: 192.168.5.33 - 192.168.5.46
Broadcast: 192.168.5.47
Network 4: 192.168.5.48
Range: 192.168.5.49 - 192.168.5.62
Broadcast: 192.168.5.63
That should give you an idea on how its done!
Let us know if it worked out for you or if you have any problems.
Cheers,
