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help with TCP/IP structure

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15 years 7 months ago #28929 by jay440
Can anyone please help me to understand the meaning/structure of the following TCP/IP network packets?


1) 13:12:49.751403 arp who-has 192.168.246.13(Broadcast) tell 192.168.246.128
2) 13:12:49.751602 arp reply 192.168.246.13is-at 00:00:01:0f:2e:7e
3) 13:12:50.441259 IP 192.168.246.13.137 > 192.168.246.128.137: UDP, length 50
4) 13:12:50.441632 IP 192.168.246.128 > 192.168.246.13: ICMP 192.168.246.128 udp port 137 unreachable, length 86
5) 13:12:51.942563 IP 192.168.246.13.137 > 192.168.246.128.137: UDP, length 50
6) 13:12:51.943277 IP 192.168.246.128 > 192.168.246.13: ICMP 192.168.246.128 udp port 137 unreachable, length 86
7) 13:12:53.444627 IP 192.168.246.13.137 > 192.168.246.128.137: UDP, length 50
8) 13:12:53.445343 IP 192.168.246.128 > 192.168.246.13: ICMP 192.168.246.128 udp port 137 unreachable, length 86
9) 13:13:02.738990 IP 192.168.246.128.39886 > 192.168.246.13.80: . ack 1611053795 win 3072
10) 13:13:02.739053 IP 192.168.246.13.80 > 192.168.246.128.39886: R 1611053795:1611053795(0) win 0
11) 13:13:22.407445 IP 192.168.246.128.54955 > 192.168.246.13.80: S 2910497703:2910497703(0) win 5840
12) 13:13:22.407560 IP 192.168.246.13.80 > 192.168.246.128.54955: S 3762608065:3762608065(0) ack 2910497704 win 64240
13) 13:13:22.407963 IP 192.168.246.128.54955 > 192.168.246.13.80: . ack 1 win 92
14) 13:13:22.408321 IP 192.168.246.128.54955 > 192.168.246.13.80: R 1:1(0) ack 1 win 92

I need help to figure out what does the sequence of packets tell me about the computer system ( which is 192.168.246.13 ) and the level of security of this computer system?
the last 6 packets are confusing and they don’t make sense to me?!?!?
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15 years 7 months ago #28938 by Arani
Replied by Arani on topic ??
Why do you want to know the security level of this computer/host?

Picking pebbles on the shore of the networking ocean
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