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Subnet Question ?!
19 years 1 month ago #10381
by splinters
Subnet Question ?! was created by splinters
I have a class A address 8.0.0.0 /23.
How do I figure out the subnet IP number of the 800th subnet?
Can someone please help me out in detail?
Thanks,
Splinters
How do I figure out the subnet IP number of the 800th subnet?
Can someone please help me out in detail?
Thanks,
Splinters
19 years 1 month ago #10386
by mew
Replied by mew on topic Re: Subnet Question ?!
If you are considering the zero subnet unusable the 800th subnet would correspond to the binary number 800.
Use a network binary place holder worksheet and place the binary number 800 such that the least significant bit is in the place of the last subnet number (this corresponds to the position of the last 1 in the subnet mask in binary). Then interpret. The binary number 1100100000 is 800.
_____2nd Octet________ 3rd Octet
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
____________ 1 1 0___ 0_ 1_ 0_ 0 0 0 0
Subnet 8.6.64.0
However if you are considering the zero subnet as the first (usable) subnet then the 800th subnet would correspond to the binary number 799 and the following would be correct. The binary number 1100011111 is 799.
_____2nd Octet________ 3rd Octet
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
____________ 1 1 0___ 0_ 0_ 1_ 1 1 1 1
Subnet 8.6.62.0
If you aren't subnetting in binary you aren't doing it the easy way :lol:
Use a network binary place holder worksheet and place the binary number 800 such that the least significant bit is in the place of the last subnet number (this corresponds to the position of the last 1 in the subnet mask in binary). Then interpret. The binary number 1100100000 is 800.
_____2nd Octet________ 3rd Octet
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
____________ 1 1 0___ 0_ 1_ 0_ 0 0 0 0
Subnet 8.6.64.0
However if you are considering the zero subnet as the first (usable) subnet then the 800th subnet would correspond to the binary number 799 and the following would be correct. The binary number 1100011111 is 799.
_____2nd Octet________ 3rd Octet
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
____________ 1 1 0___ 0_ 0_ 1_ 1 1 1 1
Subnet 8.6.62.0
If you aren't subnetting in binary you aren't doing it the easy way :lol:
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